1
IIT-JEE 2005 Screening
MCQ (Single Correct Answer)
+2
-0.5
Tangent to the curve $$y = {x^2} + 6$$ at a point $$(1, 7)$$ touches the circle $${x^2} + {y^2} + 16x + 12y + c = 0$$ at a point $$Q$$. Then the coordinates of $$Q$$ are
A
$$(-6, -11)$$
B
$$(-9, -13)$$
C
$$(-10, -15)$$
D
$$(-6, -7)$$
2
IIT-JEE 2004 Screening
MCQ (Single Correct Answer)
+2
-0.5
The angle between the tangents drawn from the point $$(1, 4)$$ to the parabola $${y^2} = 4x$$ is
A
$$\pi /6$$
B
$$\pi /4$$
C
$$\pi /3$$
D
$$\pi /2$$
3
IIT-JEE 2003 Screening
MCQ (Single Correct Answer)
+2
-0.5
The focal chord to $${y^2} = 16x$$ is tangent to $${\left( {x - 6} \right)^2} + {y^2} = 2,$$ then the possible values of the slope of the chord, are
A
$$\left\{ { - 1,\,1} \right\}$$
B
$$\left\{ { - 2,\,2} \right\}$$
C
$$\left\{ { - 2,\,-1/2} \right\}$$
D
$$\left\{ { 2,\,-1/2} \right\}$$
4
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+2
-0.5
The equation of the common tangent to the curves $${y^2} = 8x$$ and $$xy = - 1$$ is
A
$$3y = 9x + 2$$
B
$$y = 2x + 1$$
C
$$2y = x + 8$$
D
$$y= x + 2$$
JEE Advanced Subjects