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Straight Lines and Pair of Straight Lines
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Limits, Continuity and Differentiability
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NumericalMCQ (Single Correct Answer)MCQ (Multiple Correct Answer)Subjective1
JEE Advanced 2019 Paper 1 Offline
Numerical
+3
-0
Three lines are given by
$$r = \lambda \widehat i,\,\lambda \in R$$,
$$r = \mu (\widehat i + \widehat j),\,\mu \in R$$ and
$$r = v(\widehat i + \widehat j + \widehat k),\,v\, \in R$$
Let the lines cut the plane x + y + z = 1 at the points A, B and C respectively. If the area of the triangle ABC is $$\Delta $$ then the value of (6$$\Delta $$)2 equals ..............
$$r = \lambda \widehat i,\,\lambda \in R$$,
$$r = \mu (\widehat i + \widehat j),\,\mu \in R$$ and
$$r = v(\widehat i + \widehat j + \widehat k),\,v\, \in R$$
Let the lines cut the plane x + y + z = 1 at the points A, B and C respectively. If the area of the triangle ABC is $$\Delta $$ then the value of (6$$\Delta $$)2 equals ..............
Your input ____
2
JEE Advanced 2018 Paper 2 Offline
Numerical
+3
-0
Let P be a point in the first octant, whose image Q in the plane x + y = 3 (that is, the line segment PQ is perpendicular to the plane x + y = 3 and the mid-point of PQ lies in the plane x + y = 3) lies on the Z-axis. Let the distance of P from the X-axis be 5. If R is the image of P in the XY-plane, then the length of PR is ...............
Your input ____
3
JEE Advanced 2018 Paper 2 Offline
Numerical
+3
-0
Consider the cube in the first octant with sides OP, OQ and OR of length 1, along the X-axis, Y-axis and Z-axis, respectively, where O(0, 0, 0) is the origin. Let $$S\left( {{1 \over 2},{1 \over 2},{1 \over 2}} \right)$$ be the centre of the cube and T be the vertex of the cube opposite to the origin O such that S lies on the diagonal OT. If p = SP, q = SQ, r = SR and t = ST, then the value of |(p $$ \times $$ q) $$ \times $$ (r $$ \times $$ t)| is ............
Your input ____
4
IIT-JEE 2010 Paper 1 Offline
Numerical
+4
-0
If the distance between the plane $$Ax-2y+z=d$$ and the plane containing the lines $${{x - 1} \over 2} = {{y - 2} \over 3} = {{z - 3} \over 4}$$ and $${{x - 2} \over 3} = {{y - 3} \over 4} = {{z - 4} \over 5}\,$$ is $$\sqrt 6 \,\,,$$ then $$\left| d \right|$$ is ___________.
Your input ____
Questions Asked from Numerical
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