1
JEE Advanced 2025 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1

Let S denote the locus of the point of intersection of the pair of lines

$4x - 3y = 12\alpha$,

$4\alpha x + 3\alpha y = 12$,

where $\alpha$ varies over the set of non-zero real numbers. Let T be the tangent to S passing through the points $(p, 0)$ and $(0, q)$, $q > 0$, and parallel to the line $4x - \frac{3}{\sqrt{2}} y = 0$.

Then the value of $pq$ is :

A

$-6\sqrt{2}$

B

$-3\sqrt{2}$

C

$-9\sqrt{2}$

D

$-12\sqrt{2}$

2
JEE Advanced 2013 Paper 1 Offline
MCQ (Single Correct Answer)
+4
-1
For $$a > b > c > 0,$$ the distance between $$(1, 1)$$ and the point of intersection of the lines $$ax + by + c = 0$$ and $$bx + ay + c = 0$$ is less than $$\left( {2\sqrt 2 } \right)$$. Then
A
$$a + b - c > 0$$
B
$$a - b + c < 0$$
C
$$a - b + c = > 0$$
D
$$a + b - c < 0$$
3
IIT-JEE 2011 Paper 1 Offline
MCQ (Single Correct Answer)
+4
-1
A straight line $$L$$ through the point $$(3, -2)$$ is inclined at an angle $${60^ \circ }$$ to the line $$\sqrt {3x} + y = 1.$$ If $$L$$ also intersects the x-axis, then the equation of $$L$$ is
A
$$y + \sqrt {3x} + 2 - 3\sqrt 3 = 0$$
B
$$y - \sqrt {3x} + 2 + 3\sqrt 3 = 0$$
C
$$\sqrt {3y} - x + 3 + 2\sqrt 3 = 0$$
D
$$\sqrt {3y} + x - 3 + 2\sqrt 3 = 0$$
4
IIT-JEE 2008 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

Consider three points $$P = ( - \sin (\beta - \alpha ), - cos\beta ),Q = (cos(\beta - \alpha ),\sin \beta )$$ and $$R = (\cos (\beta - \alpha + \theta ),\sin (\beta - \theta ))$$ where $$0 < \alpha ,\beta ,\theta < {\pi \over 4}$$. Then :

A
P lies on the line segment RQ
B
Q lies on the line segment PR
C
R lies on the line segment QP
D
P, Q, R are non-collinear
JEE Advanced Subjects