1
IIT-JEE 2008 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

Consider three points $$P = ( - \sin (\beta - \alpha ), - cos\beta ),Q = (cos(\beta - \alpha ),\sin \beta )$$ and $$R = (\cos (\beta - \alpha + \theta ),\sin (\beta - \theta ))$$ where $$0 < \alpha ,\beta ,\theta < {\pi \over 4}$$. Then :

A
P lies on the line segment RQ
B
Q lies on the line segment PR
C
R lies on the line segment QP
D
P, Q, R are non-collinear
2
IIT-JEE 2008 Paper 2 Offline
MCQ (Single Correct Answer)
+4
-1

Consider the lines given by:

$${L_1}:x + 3y - 5 = 0$$

$${L_2}:3x - ky - 1 = 0$$

$${L_3}:5x + 2y - 12 = 0$$

Match the Statement/Expressions in Column I with the Statements/Expressions in Column II.

Column I Column II
(A) L$$_1$$, L$$_2$$, L$$_3$$ are concurrent, if (P) $$K = - 9$$
(B) One of L$$_1$$, L$$_2$$, L$$_3$$ is parallel to atleast one of the other two, if (Q) $$K = - {6 \over 5}$$
(C) L$$_1$$, L$$_2$$, L$$_3$$ form a triangle, if (R) $$K = {5 \over 6}$$
(D) L$$_1$$, L$$_2$$, L$$_3$$ do not form a triangle, if (S) $$K = 5$$

A
A - iv; B - ii; C - iii; D - i, ii
B
A - iv; B - i, ii; C - iii; D - i, ii, iv
C
A - iv; B - i; C - iii; D - i, ii
D
A - ii; B - i, iii; C - iii; D - i, ii, iv
3
IIT-JEE 2008 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

Let a and b be non-zero real numbers. Then, the equation

$$(a{x^2} + b{y^2} + c)({x^2} - 5xy + 6{y^2}) = 0$$ represents :

A
four straight lines, when c = 0 and a, b are of the same sign
B
two straight lines and a circle, when a = b, and c is of sign opposite to that of a
C
two straight lines and a hyperbola, when a and b are of the same sign and c is of sign opposite to that of a
D
a circle and an ellipse, when a and b are of the same sign and c is of sign opposite to that of a
4
IIT-JEE 2007
MCQ (Single Correct Answer)
+3
-0.75
The lines $${L_1}:y - x = 0$$ and $${L_2}:2x + y = 0$$ intersect the line $${L_3}:y + 2 = 0$$ at $$P$$ and $$Q$$ respectively. The bisector of the acute angle between $${L_1}$$ and $${L_2}$$ intersects $${L_3}$$ at $$R$$.

Statement-1: The ratio $$PR$$ : $$RQ$$ equals $$2\sqrt 2 :\sqrt 5 $$. because
Statement-2: In any triangle, bisector of an angle divides the triangle into two similar triangles.

A
Statement-1 is True, Statement-2 is True; Statement-2 is not a correct explanation for Statement- 1
B
Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.
C
Statement-1 is True, Statement-2 is False.
D
Statement-1 is False, Statement-2 is True.
JEE Advanced Subjects