1
IIT-JEE 2001 Screening
MCQ (Single Correct Answer)
+2
-0.5
The triangle formed by the tangent to the curve $$f\left( x \right) = {x^2} + bx - b$$ at the point $$(1, 1)$$ and the coordinate axex, lies in the first quadrant. If its area is $$2$$, then the value of $$b$$ is
A
$$-1$$
B
$$3$$
C
$$-3$$
D
$$1$$
2
IIT-JEE 2001 Screening
MCQ (Single Correct Answer)
+2
-0.5
If $$f\left( x \right) = x{e^{x\left( {1 - x} \right)}},$$ then $$f(x)$$ is
A
increasing on $$\left[ { - 1/2,1} \right]$$
B
decreasing on $$R$$
C
increasing on $$R$$
D
decreasing on $$\left[ { - 1/2,1} \right]$$
3
IIT-JEE 2000 Screening
MCQ (Single Correct Answer)
+2
-0.5
Let $$f\left( x \right) = \int {{e^x}\left( {x - 1} \right)\left( {x - 2} \right)dx.} $$ Then $$f$$ decreases in the interval
A
$$\left( { - \infty ,2} \right)$$
B
$$\left( { - 2, - 1} \right)$$
C
$$\left( {1,2} \right)$$
D
$$\left( {2, + \infty } \right)$$
4
IIT-JEE 2000 Screening
MCQ (Single Correct Answer)
+2
-0.5
If the normal to the curve $$y = f\left( x \right)$$ and the point $$(3, 4)$$ makes an angle $${{{3\pi } \over 4}}$$ with the positive $$x$$-axis, then $$f'\left( 3 \right) = $$
A
$$-1$$
B
$$ - {3 \over 4}$$
C
$${4 \over 3}$$
D
$$1$$
JEE Advanced Subjects