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MCQ (Multiple Correct Answer)Modern Physics
1
JEE Advanced 2013 Paper 2 Offline
MCQ (More than One Correct Answer)
+3
-0.75
Using the expression $$2d\sin \theta = \lambda $$, one calculates the values of d by measuring the corresponding angles $$\theta $$ in
the range 0 to 90o. The wavelength $$\lambda $$ is exactly known and the error in $$\theta $$ is constant for all values of $$\theta $$. As $$\theta $$ increases from 0o
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JEE Advanced Subjects
Physics
Mechanics
Electricity
Modern Physics
Chemistry
Physical Chemistry
Inorganic Chemistry
Mathematics
Algebra
Trigonometry
Coordinate Geometry