1
JEE Advanced 2015 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2
For photo-electric effect with incident photon wavelength $$\lambda$$, the stopping potential is V0. Identify the correct variation(s) of V0 with $$\lambda$$ and $${1 \over \lambda }$$.
A
JEE Advanced 2015 Paper 1 Offline Physics - Dual Nature of Radiation Question 18 English Option 1
B
JEE Advanced 2015 Paper 1 Offline Physics - Dual Nature of Radiation Question 18 English Option 2
C
JEE Advanced 2015 Paper 1 Offline Physics - Dual Nature of Radiation Question 18 English Option 3
D
JEE Advanced 2015 Paper 1 Offline Physics - Dual Nature of Radiation Question 18 English Option 4
2
JEE Advanced 2013 Paper 2 Offline
MCQ (More than One Correct Answer)
+3
-0.75
Using the expression $$2d\sin \theta = \lambda $$, one calculates the values of d by measuring the corresponding angles $$\theta $$ in the range 0 to 90o. The wavelength $$\lambda $$ is exactly known and the error in $$\theta $$ is constant for all values of $$\theta $$. As $$\theta $$ increases from 0o
A
the absolute error in d remains constant
B
the absolute error in d increases
C
the fractional error in d remains constant
D
the fractional error in d decreases
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