1
IIT-JEE 2012 Paper 2 Offline
MCQ (Single Correct Answer)
+4
-1
The electrochemical cell shown below is a concentration cell. M | M2+ (saturated solution of a sparingly soluble salt, MX2) || M2+ (0.001 mol dm–3) | M The emf of the cell depends on the difference in concentrations of M2+ ions at the two electrodes. The emf of the cell at 298 K is 0.059 V.

The solubility product (Ksp; mol3 dm–9) of MX2 at 298 K based on the information available for the given concentration cell is (take 2.303 $$\times$$ R $$\times$$ 298/F = 0.059 V)
A
1 $$\times$$ 10–15
B
4 $$\times$$ 10–15
C
1 $$\times$$ 10–12
D
4 $$\times$$ 10–12
2
IIT-JEE 2012 Paper 2 Offline
MCQ (Single Correct Answer)
+4
-1
The electrochemical cell shown below is a concentration cell. M | M2+ (saturated solution of a sparingly soluble salt, MX2) || M2+ (0.001 mol dm–3) | M The emf of the cell depends on the difference in concentrations of M2+ ions at the two electrodes. The emf of the cell at 298 K is 0.059 V.

The value of ∆G (kJ mol–1) for the given cell is (take 1F = 96500 C mol–1)
A
–5.7
B
5.7
C
11.4
D
-11.4
3
IIT-JEE 2011 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

AgNO3(aq.) was added to an aqueous KCl solution gradually and the conductivity of the solution was measured. The plot of conductance ($$\Lambda $$) versus the volume of AgNO3 is

IIT-JEE 2011 Paper 1 Offline Chemistry - Electrochemistry Question 10 English

A
(P)
B
(Q)
C
(R)
D
(S)
4
IIT-JEE 2011 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Consider the following cell reaction:
2Fe(s) + O2(g) + 4H+(aq) $$\to$$ 2Fe2+ (aq) + 2H2O (l); Eo = 1.67 V
At [Fe2+] = 10-3 M, P(O2) = 0.1 atm and pH = 3, the cell potential at 25oC is
A
1.47 V
B
1.77 V
C
1.87 V
D
1.57 V
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