1
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Match the LIST-I with LIST-II

LIST-I (Reagent)LIST-II (Functional Group detected)
A. Sodium bicarbonate solutionI. double bond/unsaturation
B. Neutral ferric chlorideII. carboxylic acid
C. ceric ammonium nitrateIII. phenolic - OH
D. alkaline KMnO4IV. alcoholic - OH

Choose the correct answer from the options given below:

A

A-II, B-III, C-I, D-IV

B

A-II, B-IV, C-III, D-I

C

A-III, B-II, C-IV, D-I

D

A-II, B-III, C-IV, D-I

2
JEE Main 2025 (Online) 7th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Which of the following compounds is least likely to give effervescence of $\mathrm{CO}_2$ in presence of aq. $\mathrm{NaHCO}_3 ?$

A
JEE Main 2025 (Online) 7th April Morning Shift Chemistry - Salt Analysis Question 4 English Option 1
B
JEE Main 2025 (Online) 7th April Morning Shift Chemistry - Salt Analysis Question 4 English Option 2
C
JEE Main 2025 (Online) 7th April Morning Shift Chemistry - Salt Analysis Question 4 English Option 3
D
JEE Main 2025 (Online) 7th April Morning Shift Chemistry - Salt Analysis Question 4 English Option 4
3
JEE Main 2025 (Online) 7th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Given below are two statements :

Statement I : Mohr's salt is composed of only three types of ions-ferrous, ammonium and sulfate.

Statement II : If the molar conductance at infinite dilution for ferrous, ammonium and sulfate ions are $x_1, x_2$ and $x_3 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$, respectively then the molar conductance for Mohr's salt solution at infinite dilution would be given by $x_1+x_2+2 x_3$

In the light of the given statements, choose the correct answer from the options given below :

A
Both Statements I and Statement II are true
B
  Statement I is true but Statement II are false
C
Both Statements I and Statement II are false
D
Statement I is false but Statement II is true
4
JEE Main 2025 (Online) 7th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

When a salt is treated with sodium hydroxide solution it gives gas X . On passing gas X through reagent Y a brown coloured precipitate is formed. X and Y respectively, are

A
$\mathrm{X}=\mathrm{NH}_3$ and $\mathrm{Y}=\mathrm{HgO}$
B
$\mathrm{X}=\mathrm{NH}_4 \mathrm{Cl}$ and $\mathrm{Y}=\mathrm{KOH}$
C
$\mathrm{X}=\mathrm{NH}_3$ and $\mathrm{Y}=\mathrm{K}_2 \mathrm{HgI}_4+\mathrm{KOH}$
D
$\mathrm{X}=\mathrm{HCl}$ and $\mathrm{Y}=\mathrm{NH}_4 \mathrm{Cl}$
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