Electromagnetism
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Alternating Current
MCQ (Single Correct Answer)
Modern Physics
Dual Nature of Radiation
MCQ (Single Correct Answer)
Semiconductor Devices and Logic Gates
MCQ (Single Correct Answer)
Communication Systems
MCQ (Single Correct Answer)
1
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The angle of banking '$$\theta$$' for a meter gauge railway line is given by $$\theta=\tan ^{-1}\left(\frac{1}{20}\right)$$. What is the elevation of the outer rail above the inner rail?

A
$$20 \mathrm{~cm}$$
B
$$10 \mathrm{~cm}$$
C
$$0.2 \mathrm{~cm}$$
D
$$5 \mathrm{~cm}$$
2
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A particle moves in a circular orbit of radius '$$r$$' under a central attractive force, $$F=-\frac{k}{r}$$, where $$\mathrm{k}$$ is a constant. The periodic time of its motion is proportional to

A
$$r^{\frac{1}{2}}$$
B
$$\mathrm{r}^{\frac{2}{3}}$$
C
$$r$$
D
$$r^{\frac{3}{2}}$$
3
MHT CET 2021 20th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle at rest starts moving with a constant angular acceleration of $$4 \mathrm{~rad} / \mathrm{s}^2$$ in a circular path. At what time the magnitude of its centripetal acceleration and tangential acceleration will be equal?

A
$$\frac{1}{4} \mathrm{~S}$$
B
$$\frac{2}{3} \mathrm{~S}$$
C
$$\frac{1}{2} \mathrm{~S}$$
D
$$\frac{1}{3} \mathrm{~S}$$
4
MHT CET 2020 19th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

A child starts running from rest along a circular track of radius $r$ with constant tangential acceleration a. After time $t$ he feels that slipping of shoes on the ground has started. The coefficient of friction between shoes and the ground is

[g = acceleration due to gravity]

A
$\frac{\left[a^4 t^4+a^2 r^2\right]^{\frac{1}{2}}}{g r}$
B
$\frac{\left[a^4 t^4+a^2 r^2\right]}{r g}$
C
$\frac{\left[a^2 t^2+a^4 r^4\right]}{r g}$
D
$\frac{\left[a^4 t^4-a^2 r^2\right]^{\frac{1}{2}}}{r g}$
MHT CET Subjects