Electromagnetism
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Alternating Current
MCQ (Single Correct Answer)
Modern Physics
Dual Nature of Radiation
MCQ (Single Correct Answer)
Semiconductor Devices and Logic Gates
MCQ (Single Correct Answer)
Communication Systems
MCQ (Single Correct Answer)
1
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle performing uniform circular motion of radius $$\frac{\pi}{2} \mathrm{~m}$$ makes '$$\mathrm{x}$$' revolutions in time '$$t$$'. Its tangential velocity is

A
$$\frac{\pi \mathrm{x}}{\mathrm{t}}$$
B
$$\frac{\pi x^2}{t}$$
C
$$\frac{\pi^2 x^2}{t}$$
D
$$\frac{\pi^2 \mathrm{x}}{\mathrm{t}}$$
2
MHT CET 2023 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A body of mass 200 gram is tied to a spring of spring constant $$12.5 \mathrm{~N} / \mathrm{m}$$, while other end of spring is fixed at point '$$O$$'. If the body moves about '$$O$$' in a circular path on a smooth horizontal surface with constant angular speed $$5 \mathrm{~rad} / \mathrm{s}$$ then the ratio of extension in the spring to its natural length will be

MHT CET 2023 10th May Morning Shift Physics - Circular Motion Question 44 English

A
1 : 2
B
1 : 1
C
2 : 3
D
2 : 5
3
MHT CET 2023 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle of mass '$$\mathrm{m}$$' moves along a circle of radius '$$r$$' with constant tangential acceleration. If K.E. of the particle is '$$E$$' by the end of third revolution after beginning of the motion, then magnitude of tangential acceleration is

A
$$\frac{\mathrm{E}}{2 \pi \mathrm{rm}}$$
B
$$\frac{\mathrm{E}}{6 \pi \mathrm{rm}}$$
C
$$\frac{\mathrm{E}}{8 \pi \mathrm{rm}}$$
D
$$\frac{\mathrm{E}}{4 \pi \mathrm{rm}}$$
4
MHT CET 2023 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A simple pendulum of length $$2 \mathrm{~m}$$ is given a horizontal push through angular displacement of $$60^{\circ}$$. If the mass of bob is 200 gram, the angular velocity of the bob will be (Take Acceleration due to gravity $$=10 \mathrm{~m} / \mathrm{s}^2$$ ) $$\left(\sin 30^{\circ}=\cos 60^{\circ}=0.5, \cos 30^{\circ}=\sin 60^{\circ}=\sqrt{3} / 2\right)$$

A
$$2 \sqrt{2} ~\mathrm{rad} / \mathrm{s}$$
B
$$3 \sqrt{2} ~\mathrm{rad} / \mathrm{s}$$
C
$$2 \sqrt{2.5} ~\mathrm{rad} / \mathrm{s}$$
D
$$3 \sqrt{2.5} ~\mathrm{rad} / \mathrm{s}$$
MHT CET Subjects