Electromagnetism
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Alternating Current
MCQ (Single Correct Answer)
Modern Physics
Dual Nature of Radiation
MCQ (Single Correct Answer)
Semiconductor Devices and Logic Gates
MCQ (Single Correct Answer)
Communication Systems
MCQ (Single Correct Answer)
1
MHT CET 2020 19th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

A child starts running from rest along a circular track of radius $r$ with constant tangential acceleration a. After time $t$ he feels that slipping of shoes on the ground has started. The coefficient of friction between shoes and the ground is

[g = acceleration due to gravity]

A
$\frac{\left[a^4 t^4+a^2 r^2\right]^{\frac{1}{2}}}{g r}$
B
$\frac{\left[a^4 t^4+a^2 r^2\right]}{r g}$
C
$\frac{\left[a^2 t^2+a^4 r^4\right]}{r g}$
D
$\frac{\left[a^4 t^4-a^2 r^2\right]^{\frac{1}{2}}}{r g}$
2
MHT CET 2020 19th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

A body is moving along a circular track of radius 100 m with velocity $20 \mathrm{~m} / \mathrm{s}$. Its tangential acceleration is $3 \mathrm{~m} / \mathrm{s}^2$, then its resultant acceleration will be

A
$5 \mathrm{~m} / \mathrm{s}^2$
B
$4 \mathrm{~m} / \mathrm{s}^2$
C
$2 \mathrm{~m} / \mathrm{s}^2$
D
$3 \mathrm{~m} / \mathrm{s}^2$
3
MHT CET 2020 16th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle starting from rest moves along the circumference of a circle of radius $$r$$ with angular acceleration $$\alpha$$. The magnitude of the average velocity, in the time it completes the small angular displacement $$\theta$$ is

A
$$r\left(\frac{2}{\alpha \theta}\right)^2$$
B
$$r\left(\frac{\alpha \theta}{2}\right)^2$$
C
$$\rho\left(\frac{\alpha \theta}{2}\right)$$
D
$$r\left(\frac{\alpha \theta}{2}\right)^{\frac{1}{2}}$$
4
MHT CET 2020 16th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle of mass $$m$$ is performing UCM along a circle of radius $$r$$. The relation between centripetal acceleration $$a$$ and kinetic energy $$E$$ is given by

A
$$a=\frac{2 E}{m r}$$
B
$$a=2 E m$$
C
$$a=\frac{E}{m r}$$
D
$$a=\left(\frac{2 E}{m r}\right)^2$$
MHT CET Subjects