WB JEE 2025 | Heat and Thermodynamics Question 8 | Physics

Let $\bar{V}, V_{m s}, V_p$ denotes the mean speed, root mean square speed and most probable speed of the molecules each of mass $m$ in an ideal monoatomic gas at absolute temperature $T$ Kelvin. Which statement(s) is/are correct?

No molecules can have speed greater than $\sqrt{2} V_{m s}$.

No molecules can have speed less than $V_p / \sqrt{2}$.

$V_p< \bar{V}< V_{m s}$

Average kinetic energy of a molecule is $\frac{3}{4} m V_P^2$.

WB JEE 2023

MCQ (More than One Correct Answer)

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WB JEE 2023 Physics - Heat and Thermodynamics Question 9 English

A cyclic process is shown in p-v diagram and T-S diagram. Which of the following statements is/are true?

1$$\to$$2 : Isobaric, 2$$\to$$3 : Isothermal.

3$$\to$$1 : Isochoric, 2$$\to$$3 : adiabatic.

Work done by the system in the complete cyclic process is non-zero.

The heat absorbed by the system in the complete cyclic process is non-zero.

WB JEE 2021

MCQ (More than One Correct Answer)

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WB JEE 2021 Physics - Heat and Thermodynamics Question 21 English

Consider the p - V diagram for 1 mole of an ideal monatomic gas shown in the figure. Which of the following statements is/are true?

The change in internal energy for the whole process is zero.

Heat is rejected during the process.

Change in internal energy for process A $$\to$$ B is $$ - {3 \over 2}$$p₀V₀.

Work done by the gas during the entire process is 2p₀V₀.

WB JEE 2019

MCQ (More than One Correct Answer)

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The initial pressure and volume of a given mass of an ideal gas with $$\left( {{{{C_p}} \over {{C_V}}} = \gamma } \right)$$, taken in a cylinder fitted with a piston, are p₀ and V₀ respectively. At this stage the gas has the same temperature as that of the surrounding medium which is T₀. It is adiabatically compressed to a volume equal to $${{{V_0}} \over 2}$$. Subsequently the gas is allowed to come to thermal equilibrium with the surroundings. What is the heat released to the surrounding?

$$({2^{\gamma - 1}} - 1){{{p_0}V} \over {\gamma - 1}}$$

$$\gamma {p_0}{V_0}In2$$

$${{{p_0}V} \over {2(\gamma - 1)}}$$

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