WB JEE 2022 | Wave Optics Question 7 | Physics

In a Young's double slit experiment, the intensity of light at a point on the screen where the path difference between the interfering waves is $$\lambda$$, ($$\lambda$$ being the wavelength of light used) is I. The intensity at a point where the path difference is $${\lambda \over 4}$$ will be (assume two waves have same amplitude)

zero

$${I \over 2}$$

$${I \over 4}$$

WB JEE 2022

MCQ (Single Correct Answer)

-0.25

In Young's double slit experiment with a monochromatic light, maximum intensity is 4 times the minimum intensity in the interference pattern. What is the ratio of the intensities of the two interfering waves?

1/9

1/3

1/16

1/2

WB JEE 2021

MCQ (Single Correct Answer)

-0.25

In Young's double slit experiment, light of wavelength $$\lambda$$ passes through the double slit and forms interference fringes on a screen 1.2 m away. If the difference between 3rd order maximum and 3rd order minimum is 0.18 cm and the slits are 0.02 cm apart, then $$\lambda$$ is

1200 nm

450 nm

600 nm

300 nm

WB JEE 2020

MCQ (Single Correct Answer)

-0.25

The intensity of light emerging from one of the slits in a Young's double slit experiment is found to be 1.5 times the intensity of light emerging from the other slit. What will be the approximate ratio of intensity of an interference maximum to that of an interference minimum?

2.25

9.9

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