IAT (IISER) 2020 | Laws of Motion Question 1 | Physics

Consider a mass-pulley system as shown in the figure. There is a wedge of mass $M$ and equal wedge angles $\theta$ lying on a rigid horizontal table. The coefficient of friction between the wedge and the table is $\mu$. There are two blocks of mass $m_1$ and $m_2$ lying on the incline of the wedge. The coefficients of friction between the blocks and wedge are $\mu_1$ and $\mu_2$ as shown in the figure. Consider $m_1>m_2$ and the coefficients of friction ( $\mu, \mu_1$ and $\mu_2$ ) to be less than $\tan \theta$. Gravity is acting downwards with acceleration due to gravity $g$. What should be the value of $\frac{m_1}{m_2}$ so that the system is in equilibrium?

IAT (IISER) 2020 Physics - Laws of Motion Question 1 English

$\frac{\mu_1 \mu_2 \cos \theta+\sin \theta}{\sin \theta-\mu \cos \theta}$

$\frac{\mu_1 \cos \theta+\sin \theta}{\sin \theta-\mu_2 \cos \theta}$

$\frac{\mu_2 \cos \theta+\sin \theta}{\sin \theta-\mu_1 \cos \theta}$

$\frac{\mu \cos \theta+\sin \theta}{\sin \theta-\mu_1 \cos \theta}$

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