1
WB JEE 2025
MCQ (Single Correct Answer)
+1
-0.25

$$\begin{aligned} &{ }_5 \mathrm{~B}^{10}+{ }_2 \mathrm{He}^4 \rightarrow \mathrm{X}+{ }_0 \mathrm{n}^1\\ &\text { In the above nuclear reaction ' } X \text { ' will be } \end{aligned}$$

A
${ }_7 \mathrm{~N}^{14}$
B
${ }_7 \mathrm{~N}^{13}$
C
${ }_6 \mathrm{C}^{12}$
D
${ }_7 \mathrm{~N}^{12}$
2
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25

After the emission of a $$\beta$$-particle followed by an $$\alpha$$-particle from $${ }_{83}^{214} \mathrm{Bi}$$, the number of neutrons in the atom is -

A
210
B
128
C
129
D
82
3
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25

If in case of a radio isotope the value of half-life (T$$_{1/2}$$) and decay constant ($$\lambda$$) are identical in magnitude, then their value should be

A
0.693/2
B
(0.693)$$^{1/2}$$
C
(0.693)$$^2$$
D
0.693
4
WB JEE 2021
MCQ (Single Correct Answer)
+1
-0.25
For the reaction $$_7^{14}N(\alpha ,p)\,{}^{17}O$$, 1.16 MeV (Mass equivalent = 0.00124 amu) of energy is absorbed. Mass on the reactant side is 18.00567 amu and proton mass = 1.00782 amu. The atomic mass of $${}^{17}O$$ will be
A
17.0044 amu
B
16.9991 amu
C
17.0114 amu
D
16.9966 amu
WB JEE Subjects