AP EAPCET 2024 - 23th May Morning Shift | Semiconductor Devices and Logic Gates Question 1 | Physics | AP EAPCET - ExamSIDE.Com

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1

AP EAPCET 2024 - 23th May Morning Shift

MCQ (Single Correct Answer)

+1

-0

In the diodes show in the diagrams, which one is reverse biased?

A

AP EAPCET 2024 - 23th May Morning Shift Physics - Semiconductor Devices and Logic Gates Question 2 English Option 1

B

AP EAPCET 2024 - 23th May Morning Shift Physics - Semiconductor Devices and Logic Gates Question 2 English Option 2

C

AP EAPCET 2024 - 23th May Morning Shift Physics - Semiconductor Devices and Logic Gates Question 2 English Option 3

D

AP EAPCET 2024 - 23th May Morning Shift Physics - Semiconductor Devices and Logic Gates Question 2 English Option 4

2

AP EAPCET 2024 - 23th May Morning Shift

MCQ (Single Correct Answer)

+1

-0

$$ \text { The following configuration of gates is equivalent to } $$

AP EAPCET 2024 - 23th May Morning Shift Physics - Semiconductor Devices and Logic Gates Question 1 English

A

NAND

B

$X O R$

C

AND

D

$O R$

3

AP EAPCET 2024 - 22th May Evening Shift

MCQ (Single Correct Answer)

+1

-0

$$ \text { Truth table for the given circuit is } $$

AP EAPCET 2024 - 22th May Evening Shift Physics - Semiconductor Devices and Logic Gates Question 3 English

A

$$ \begin{array}{lll} \hline A & B & Y \\ \hline 0 & 0 & 1 \\ \hline 0 & 1 & 0 \\ \hline 1 & 0 & 1 \\ \hline 1 & 1 & 1 \\ \hline \end{array} $$

B

$$ \begin{array}{lll} \hline A & B & Y \\ \hline 0 & 0 & 1 \\ \hline 0 & 1 & 1 \\ \hline 1 & 0 & 0 \\ \hline 1 & 1 & 1 \\ \hline \end{array} $$

C

$$ \begin{array}{lll} \hline A & B & Y \\ \hline 0 & 0 & 1 \\ \hline 0 & 1 & 1 \\ \hline 1 & 0 & 1 \\ \hline 1 & 1 & 1 \\ \hline \end{array} $$

D

$$ \begin{array}{lll} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ \hline 0 & 1 & 1 \\ \hline 1 & 0 & 1 \\ \hline 1 & 1 & 1 \\ \hline \end{array} $$

4

AP EAPCET 2024 - 22th May Evening Shift

MCQ (Single Correct Answer)

+1

-0

If $R_C$ and $R_B$ are respectively the resistances of in collector and base sides of the circuit and $\beta$ is the current amplification factor, then the voltage gain of a transistor amplifier in common emitter configuration is

A

$\beta R_C R_B$

B

$\frac{\beta}{R_C R_B}$

C

$\frac{\beta R_B}{R_C}$

D

$\frac{\beta R_C}{R_B}$

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