WB JEE 2021 | Dual Nature of Radiation Question 6 | Physics

Electric field component of an EM radiation varies with time as E = a (cos$$\omega$$₀t + sin$$\omega$$t cos$$\omega$$₀t), where a is a constant and $$\omega$$ = 10¹⁵ s^$$-$$1, $$\omega$$₀ = 5 $$\times$$ 10¹⁵ s^$$-$$1. This radiation falls on a metal whose stopping potential is $$-$$2 eV. Then, which of the following statements is/are true ? (h = 6.62 $$\times$$ 10^$$-$$34 J-s)

For light of frequency $$\omega$$, photoelectric effect is not possible.

Stopping potential versus frequency graph will be a straight line.

The work function of the mutual is $$-$$2 eV.

The maximum kinetic energy of the photoelectrons is $$-$$2 eV.

WB JEE 2020

MCQ (More than One Correct Answer)

-0

A point source of light is used in an experiment of photoelectric effects. If the distance between the source and the photoelectric surface is doubled, which of the following may result?

Stopping potential will be halved.

Photoelectric current will decrease.

Maximum kinetic energy of photoelectrons will decrease.

Stopping potential will increase slightly.

WB JEE 2019

MCQ (More than One Correct Answer)

-0

Electrons are emitted with kinetic energy T from a metal plate by an irradiation of light of intensity J and frequency v. Then, which of the following will be true?

T $$ \propto $$ J

T linearly increasing with v

T $$ \propto $$ time of irradiation

Number of electrons emitted $$ \propto $$ J

WB JEE 2016

MCQ (More than One Correct Answer)

-0

The distance between a light source and photoelectric cell is d. If the distance is decreased to $${d \over 2}$$, then

the emission of electron per second will be four times

maximum kinetic energy of photoelectrons will be four times

stopping potential will remain same

the emission of electrons per second will be doubled

Questions Asked from MCQ (Multiple Correct Answer)

WB JEE 2024 (1) WB JEE 2021 (1) WB JEE 2020 (1) WB JEE 2019 (1) WB JEE 2016 (1)

WB JEE Subjects