WB JEE 2020 | Laws of Motion Question 13 | Physics

A block of mass m rests on a horizontal table with a coefficient of static friction $$\mu $$. What minimum force must be applied on the block to drag it on the table?

$${\mu \over {\sqrt {1 + {\mu ^2}} }}$$ mg

$${{\mu - 1} \over {\mu + 1}}$$ mg

$${\mu \over {\sqrt {1 - {\mu ^2}} }}$$ mg

$$\mu $$ mg

WB JEE 2019

MCQ (Single Correct Answer)

-0.25

Two weights of the mass m₁ and m₂ (> m₁) are joined by an inextensible string of negligible mass passing over a fixed frictionless pulley. The magnitude of the acceleration of the loads is

$${{{m_2} - {m_1}} \over {{m_2}}}$$

$${{{m_1}} \over {{m_2} + {m_1}}}g$$

$${{{m_2} - {m_1}} \over {{m_2} + {m_1}}}g$$

WB JEE 2018

MCQ (Single Correct Answer)

-0.25

A block of mass m₂ is placed on a horizontal table and another block of mass m₁ is placed on top of it. An increasing horizontal force F = at is exerted on the upper block but the lower block never moves as a result. If the coefficient of friction between the blocks is $$\mu$$₁ and that between the lower block and the table is $$\mu$$₂, then what is the maximum possible value of $$\mu$$₁ / $$\mu$$₂ ?

$${{{m_2}} \over {{m_1}}}$$

1 + $${{{m_2}} \over {{m_1}}}$$

$${{{m_1}} \over {{m_2}}}$$

1 + $${{{m_1}} \over {{m_2}}}$$

WB JEE 2018

MCQ (Single Correct Answer)

-0.25

The velocity (v) of a particle (under a force F) depends on its distance (x) from the origin (with x > 0) $$v \propto {1 \over {\sqrt x }}$$. Find how the magnitude of the force (F) on the particle depends on x?

$$F \propto {1 \over {{x^{3/2}}}}$$

$$F \propto {1 \over x}$$

$$F \propto {1 \over {{x^2}}}$$

$$F \propto x$$

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