BITSAT 2024 | Properties of Triangles Question 2 | Mathematics

$ A B C $ is a triangular park with $ A B=A C=100 \mathrm{~m} $. A TV tower stands at the mid-point of $ B C $. The angles of elevation of the top of the tower at $ A $, $ B, C $ are $ 45^{\circ}, 60^{\circ}, 60^{\circ} $ respectively. The height of the tower is

50 m

$ 50 \sqrt{3} \mathrm{~m} $

$ 50 \sqrt{2} \mathrm{~m} $

$ 50(3-\sqrt{3}) \mathrm{m} $

BITSAT 2023

MCQ (Single Correct Answer)

-1

Let $$\frac{\sin A}{\sin B}=\frac{\sin (A-C)}{\sin (C-B)}$$, where $$A, B$$ and $$C$$ are angles of a $$\triangle A B C$$. If the lengths of the sides opposite these angles are $$a, b$$ and $$c$$ respectively, then

$$b^2-a^2=a^2+c^2$$

$$b^2, c^2, a^2$$ are in AP

$$c^2, a^2, b^2$$ are in AP

$$a^2, b^2, c^2$$ are in AP

BITSAT 2022

MCQ (Single Correct Answer)

-1

Let $$\alpha$$ be the solution of $${16^{{{\sin }^2}\theta }} + {16^{{{\cos }^2}\theta }} = 10$$ in $$\left( {0,{\pi \over 4}} \right)$$. If the shadow of a vertical pole is $${1 \over {\sqrt 3 }}$$ of its height, then the altitude of the sun is

$$\alpha$$

$${\alpha \over 2}$$

$$2\alpha$$

$${\alpha \over 3}$$

BITSAT 2022

MCQ (Single Correct Answer)

-1

Given that a house forms a right angle view from a window of another house, and the angle of elevation from the base of the first house to the window is 60 degrees. If the separation between the two houses is 6 meters, calculate the height of the first house.

8$$\sqrt3$$ m

6$$\sqrt3$$ m

4$$\sqrt3$$ m

None of these

Previous Next

Questions Asked from MCQ (Single Correct Answer)

BITSAT 2024 (2) BITSAT 2023 (1) BITSAT 2022 (3) BITSAT 2021 (1) BITSAT 2020 (1)

BITSAT Subjects

English Proficiency

Logical Reasoning

Verbal

Direction Sense Test Analogy Classification Series Completion Blood Relations Logical Deduction Logic Chart

Non Verbal

Completion of Figure Figure Formation Paper Folding and Cutting Figure Matrix Rule Detection Mirror Image