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Algebra
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Quadratic Equations
Practice Questions
MCQ (Single Correct Answer)
1
Roots of the equation $ x^{2}+b x-c=0(b, c > 0) $ are
BITSAT 2024
2
Number of real solution of $ \sqrt{5-\log _{2}|x|} $ $ =3-\log _{2}|x| $ is equal to
BITSAT 2024
3

If $$\alpha<1$$ be a root of the equation $$2 x^2-5 x+2=0$$, then the other root of the equation is

BITSAT 2023
4

Let $$\alpha, \beta$$ be the roots of the equation $$x^2-p x+r=0$$ and $$\frac{\alpha}{2}, 2 \beta$$ be the roots of the equation $$x^2-q x+r=0$$. Then, the value of $$r$$ is equal to

BITSAT 2023
5

If $$\alpha$$ be a root of the equation $$4{x^2} + 2x - 1 = 0$$, then the other root of the equation is

BITSAT 2022
6

Let a, b be the solutions of x2 + px + 1 = 0 and c, d be the solution of x2 + qx + 1 = 0. If (a $$-$$ c) (b $$-$$ c) and (a + d)(b + d) are the solution of x2 + ax + $$\beta$$ = 0, then $$\beta$$ is equal to

BITSAT 2022
7

If a$$\in$$R, b$$\in$$R, then the equation x2 $$-$$ abx $$-$$ a2 = 0 has

BITSAT 2021
8

The solution of the inequality $${4^{ - x + 0.5}} - {7.2^{ - x}} < 4$$, x $$\in$$R is

BITSAT 2021
9

Let x1 and x2 be the real roots of the equation $${x^2} - (k - 2)x + ({k^2} + 3k + 5) = 0$$, then maximum value of $$x_1^2 + x_2^2$$ is

BITSAT 2020
10

When x100 is divided by x2 $$-$$ 3x + 2, the remainder is (2k + 1 $$-$$ 1)x $$-$$(2k $$-$$ 1), then k is

BITSAT 2020
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