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Practice Questions
MCQ (Single Correct Answer)
1
Let $ [x] $ denote the greatest integer $ \leq x $. If $ f(x)=[x] $ and $ g(x)=|x| $, then the value of $ f\left(g\left(\frac{8}{5}\right)\right)-g\left(f\left(-\frac{8}{5}\right)\right) $ is
BITSAT 2024
2

If $$f(x)=x^2-2 x+1$$ and $$f \circ g(x)=x^2+2 x+1$$, then $$g(x)$$ is equal to

BITSAT 2023
3

If g(x) = x2 + x $$-$$ 2 and $$\frac{1}{2}gof(x)=2x^2-5x+2$$, then f(x) is equal to

BITSAT 2022
4

If f(x) = 4x $$-$$ x2, x$$\in$$R, and f(a + 1) $$-$$ f(a $$-$$ 1) = 0, then a is equal to

BITSAT 2021
5

The maximum value of the function y = x(x $$-$$ 1)2, is

BITSAT 2021
6

Find the area enclosed by the loop in the curve 4y2 = 4x2 $$-$$ x3.

BITSAT 2021
7

If $$2f(xy) = {(f(x))^x} + {(f(y))^x}$$ for all $$x,y \in R$$ and $$f(1) = a( \ne 1)$$. Then $$\sum\limits_{k = 1}^n {f(k) = } $$

BITSAT 2020
8

Let f(x) = x $$-$$ 3, g(x) = 4 $$-$$ x. Then the set of values of x for which $$|f(x) + g(x)|\, < \,|f(x)| + |g(x)|$$ is true, is given by :

BITSAT 2020
9

$$\left\{ {x \in R:{{2x - 1} \over {{x^3} + 4{x^2} + 3x}} \in R} \right\}$$ is equal to

BITSAT 2020
10

The solution set of $${{|x - 2|\, - 1} \over {|x - 2|\, - 2}} \le 0$$ is

BITSAT 2020
11

Let $$f(x) = {x \over {\sqrt {1 + {x^2}} }}$$, $$\underbrace {fofofo.....of(x)}_{x\,times}$$ is

BITSAT 2020
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