Algebra
Quadratic Equations
MCQ (Single Correct Answer)
Sequences and Series
MCQ (Single Correct Answer)
Permutations and Combinations
MCQ (Single Correct Answer)
Sets and Relations
MCQ (Single Correct Answer)
Three Dimensional Geometry
MCQ (Single Correct Answer)
Matrices and Determinants
MCQ (Single Correct Answer)
Mathematical Reasoning
MCQ (Single Correct Answer)
Linear Programming
MCQ (Single Correct Answer)
Trigonometry
Trigonometric Ratios & Identities
MCQ (Single Correct Answer)
Trigonometric Equations
MCQ (Single Correct Answer)
Inverse Trigonometric Functions
MCQ (Single Correct Answer)
Properties of Triangles
MCQ (Single Correct Answer)
Calculus
Limits, Continuity and Differentiability
MCQ (Single Correct Answer)
Application of Derivatives
MCQ (Single Correct Answer)
Indefinite Integration
MCQ (Single Correct Answer)
Definite Integration
MCQ (Single Correct Answer)
Area Under The Curves
MCQ (Single Correct Answer)
Differential Equations
MCQ (Single Correct Answer)
Coordinate Geometry
Straight Lines and Pair of Straight Lines
MCQ (Single Correct Answer)
1
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
If $ a > 0, b > 0, c > 0 $ and $ a, b, c $ are distinct, then $ (a+b)(b+c)(c+a) $ is greater than
A
$ 2(a+b+c) $
B
$ 3(a+b+c) $
C
$ 6 a b c $
D
$ 8 a b c $
2
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
If $ \sum\limits_{k=1}^{n} k(k+1)(k-1)=p n^{4}+q n^{3}+t n^{2}+s n $, where $ p, q, t $ and $ s $ are constants, then the value of $ s $ is equal to
A
$ -\frac{1}{4} $
B
$ -\frac{1}{2} $
C
$ \frac{1}{2} $
D
$ \frac{1}{4} $
3
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
There are four numbers of which the first three are in GP and the last three are in AP, whose common difference is 6 . If the first and the last numbers are equal, then two other numbers are
A
$ -2,4 $
B
$ -4,2 $
C
2,6
D
None of the above
4
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
The coefficient of $ x^{n} $ in the expansion of $ \frac{e^{7 x}+e^{x}}{e^{3 x}} $ is
A
$ \frac{4^{n-1}+(-2)^{n}}{n!} $
B
$ \frac{4^{n-1}+2^{n}}{n!} $
C
$ \frac{4^{n}+(-2)^{n}}{n!} $
D
$ \frac{4^{n-1}+(-2)^{n-1}}{n!} $
BITSAT Subjects
English Proficiency