Algebra
Sets and Relations
MCQ (Single Correct Answer)
Quadratic Equations
MCQ (Single Correct Answer)
Sequences and Series
MCQ (Single Correct Answer)
Permutations and Combinations
MCQ (Single Correct Answer)
Three Dimensional Geometry
MCQ (Single Correct Answer)
Matrices and Determinants
MCQ (Single Correct Answer)
Mathematical Reasoning
MCQ (Single Correct Answer)
Trigonometry
Trigonometric Ratios & Identities
MCQ (Single Correct Answer)
Trigonometric Equations
MCQ (Single Correct Answer)
Inverse Trigonometric Functions
MCQ (Single Correct Answer)
Properties of Triangles
MCQ (Single Correct Answer)
Calculus
Limits, Continuity and Differentiability
MCQ (Single Correct Answer)
Application of Derivatives
MCQ (Single Correct Answer)
Indefinite Integration
MCQ (Single Correct Answer)
Definite Integration
MCQ (Single Correct Answer)
Area Under The Curves
MCQ (Single Correct Answer)
Differential Equations
MCQ (Single Correct Answer)
Coordinate Geometry
Straight Lines and Pair of Straight Lines
MCQ (Single Correct Answer)
1
AP EAPCET 2024 - 22th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The number of ways of arranging 9 men and 5 women around circular table, so that no two women come together are
A
$8!^8 P_5$
B
$9!^9 P_5$
C
$8!^9 P_5$
D
$8!5$ !
2
AP EAPCET 2024 - 22th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If there are 6 alike fruits, 7 alike vegetables and 8 alike biscuits, then the number of ways of selecting any number of things out of them such that at least one from each category is selected, is

A
504
B
336
C
503
D
335
3
AP EAPCET 2024 - 22th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

All the letters of the word 'TABLE' are permuted and the strings of letters (may or may not have meaning) thus formed are arranged in dictionary order. Then, the rank of the word 'TABLE' counted from the rank of the word 'BLATE' is

A
50
B
97
C
61
D
37
4
AP EAPCET 2024 - 22th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
5 boys and 6 girls are arranged in all possible ways. Let $X$ denote the number of linear arrangements in which no two boys sit together and $Y$ denote the number of linear arrangements in which no two girls sit together. If $Z$ denote the number of ways of arranging all of them around a circular table such that no two boys sit together, then $X: Y: Z=$
A
$1: 1: 21$
B
$21: 1: 1$
C
$7: 5: 5$
D
$4: 3: 3$
AP EAPCET Subjects