Trigonometry
Inverse Trigonometric Functions
MCQ (Single Correct Answer)Subjective
1
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
Solution of $${(x + y)^2}{{dy} \over {dx}} = {a^2}$$ ('a' belong a constant) is
A
$${{(x + y)} \over a} = \tan {{y + C} \over a},C$$ is an arbitrary constant
B
$$xy = a\tan Cx,C$$ is an arbitrary constant
C
$${x \over a} = \tan {y \over C},C$$ is an arbitrary constant
D
$$xy = \tan (x + C),C$$ is an arbitrary constant
2
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
The integrating factor of the first order differential equation $${x^2}({x^2} - 1){{dy} \over {dx}} + x({x^2} + 1)y = {x^2} - 1$$ is
A
ex
B
$$x - {1 \over x}$$
C
$$x + {1 \over x}$$
D
$${1 \over {{x^2}}}$$
3
WB JEE 2016
MCQ (Single Correct Answer)
+1
-0.25
If the solution of the differential equation $$x{{dy} \over {dx}} + y = x{e^x}\,be\,xy = {e^x}\phi (x) + C$$, then $$\phi$$(x) is equal to
A
x + 1
B
x $$-$$ 1
C
1 $$-$$ x
D
x
4
WB JEE 2016
MCQ (Single Correct Answer)
+2
-0.5
General solution of $$y{{dy} \over {dx}} + b{y^2} = a\cos x,0 < x < 1$$ is
A
y2 = 2a(2b sin x + cos x) + ce$$-$$2bx
B
$$(4{b^2} + 1){y^2} = 2a(\sin x + 2b\cos x) + C{e^{ - 2bx}}$$
C
$$(4{b^2} + 1){y^2} = 2a(\sin x + 2b\cos x) + C{e^{ 2bx}}$$
D
$${y^2} = 2a(2b\sin x + \cos x) + C{e^{ - 2bx}}$$
WB JEE Subjects