$$\int {{e^x}\left( {{2 \over x} - {2 \over {{x^2}}}} \right)dx} $$ is equal to

The value of the integral $$\int {{{dx} \over {{{({e^x} + {e^{ - x}})}^2}}}} $$ is

$$\int {\sqrt {1 + \cos x} dx} $$ is equal to

$$\int {{{{x^3}dx} \over {1 + {x^8}}} = } $$