BITSAT 2023 | Dual Nature of Radiation Question 2 | Physics

In an electron gun the potential difference between the filament and plate is $$4000 \mathrm{~V}$$. What will be the velocity of electron emitting from the gain?

$$3 \times 10^3 \mathrm{~m} / \mathrm{s}$$

$$3.18 \times 10^7 \mathrm{~m} / \mathrm{s}$$

$$3.52 \times 10^7 \mathrm{~m} / \mathrm{s}$$

$$3.75 \times 10^7 \mathrm{~m} / \mathrm{s}$$

BITSAT 2023

MCQ (Single Correct Answer)

-1

An electron of mass $$m$$ and charge $$e$$ initially at rest gets accelerated by a constant field $$2 E$$. The rate of change of de-Broglie wavelength of this electron at time $$t$$ ignoring relativistic effects is

$$-\frac{h}{\left(2 e E t^2\right)}$$

$$\frac{-e h t}{2 E}$$

$$\left(\frac{-2 m h}{e E t^2}\right)$$

$$\left(\frac{-h}{e E}\right)$$

BITSAT 2022

MCQ (Single Correct Answer)

-1

The stopping potential (V₀) versus frequency $$\nu $$ of a graph for photoelectric effect in a metal. From the graph, the Plank's constant (h) is

BITSAT 2022 Physics - Dual Nature of Radiation Question 4 English

6.60 $$\times$$ 10^$$-$$34 J-s

6.69 $$\times$$ 10^$$-$$34 J-s

6.62 $$\times$$ 10^$$-$$34 J-s

6.63 $$\times$$ 10^$$-$$34 J-s

BITSAT 2022

MCQ (Single Correct Answer)

-1

The de-Broglie wavelength of an electron moving with a velocity $$\frac{c}{3}$$ (c = 3 $$\times$$ 10⁸ m/s) is equal to the wavelength of photon. The ratio of the kinetic energies of electron and photon is

1 : 4

1 : 3

1 : 2

2 : 1

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