Electromagnetism
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Alternating Current
MCQ (Single Correct Answer)
Modern Physics
Dual Nature of Radiation
MCQ (Single Correct Answer)
Semiconductor Devices and Logic Gates
MCQ (Single Correct Answer)
Communication Systems
MCQ (Single Correct Answer)
1
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A hemispherical portion of radius ' $R$ ' is removed from the bottom of a cylinder of radius ' R '. The volume of the remaining cylinder is ' V ' and its mass is ' M '. It is suspended by a string in a liquid of density ' $\rho$ ', where it stays vertical. The upper surface of the cylinder is at a depth ' $h$ ' below the liquid surface. The force on the bottom of the liquid is

A
Mg
B
$\mathrm{Mg}-\mathrm{V} \rho g$
C
$\mathrm{Mg}+\pi \mathrm{R}^2 \mathrm{~h} \rho g$
D
$ \mathrm{pg}\left(\mathrm{V}+\pi \mathrm{r}^2 \mathrm{~h}\right)$
2
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A water film is formed between two parallel wires of 10 cm length. The distance of 0.5 cm between the wires is increased by 1 mm . The work done in the process is (surface tension of water $=72 \mathrm{~N} / \mathrm{m}$)

A
$2.88 \times 10^{-2} \mathrm{~J}$
B
$7.2 \times 10^{-2} \mathrm{~J}$
C
$1.44 \times 10^{-2} \mathrm{~J}$
D
$3.6 \times 10^{-2} \mathrm{~J}$
3
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Identify the correct figure which shows the relation between the height of water column in a capillary tube and the capillary radius.

MHT CET 2024 4th May Evening Shift Physics - Fluid Mechanics Question 30 English

A
(B)
B
(D)
C
(A)
D
(C)
4
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Water rises up to height ' $X$ ' in a capillary tube immersed vertically in water. When the whole arrangement is taken to a depth ' d ' in a mine, the water level rises up to height ' $Y$ '. If ' $R$ ' is the radius of earth then the ratio $\frac{Y}{X}$ is

A
$\left(1-\frac{d}{R}\right)^{-1}$
B
$\left(1-\frac{d}{R}\right)$
C
$\left(1+\frac{d}{R}\right)^{-1}$
D
$\left(1+\frac{d}{R}\right)$
Questions Asked from MCQ (Single Correct Answer)
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