Electromagnetism
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Alternating Current
MCQ (Single Correct Answer)
Modern Physics
Dual Nature of Radiation
MCQ (Single Correct Answer)
Semiconductor Devices and Logic Gates
MCQ (Single Correct Answer)
Communication Systems
MCQ (Single Correct Answer)
1
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A glass tube of uniform cross-section is connected to a tap with a rubber tube. The tap is opened slowly. Initially the flow of water in the tube is streamline. The speed of flow of water to convert it into a turbulent flow is [radius of tube $$=1 \mathrm{~cm}, \eta=1 \times 10^{-3} \frac{\mathrm{Ns}}{\mathrm{m}^2}, R_n=2500$$ and density of water $$=10^3 \mathrm{~kg} / \mathrm{m}^3$$]

A
0.15 m/s
B
0.125 m/s
C
0.3 m/s
D
0.2 m/s
2
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A thin metal disc of radius 'r' floats on water surface and bends the surface downwards along the perimeter making an angle '$$\theta$$' with the vertical edge of the dsic. If the weight of water displaced by the disc is '$$\mathrm{W}$$', the weight of the metal disc is [T = surface tension of water]

A
$$2 \pi \mathrm{r} \cos \theta+W$$
B
$$\mathrm{W}-2 \pi \mathrm{T} \cos \theta$$
C
$$\mathrm{2 \pi r T+W}$$
D
$$2 \pi \mathrm{T} \cos \theta-\mathrm{W}$$
3
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

The work done in blowing a soap bubble of volume '$$\mathrm{V}$$' is '$$\mathrm{W}$$'. The work required to blow a soap bubble of volume '$$2 \mathrm{~V}$$' is [$$\mathrm{T}=$$ surface tension of soap solution]

A
$$2^{2 / 3} \mathrm{~W}$$
B
$$2 \mathrm{~W}$$
C
$$\mathrm{W}$$
D
$$2^{1 / 3} \mathrm{~W}$$
4
MHT CET 2021 23rd September Evening Shift
MCQ (Single Correct Answer)
+1
-0

A glass rod of radius '$$r_1$$' is inserted symmetrically into a vertical capillary tube of radius '$$r_2$$' ($$r_1 < \mathrm{r}_2$$) such that their lower ends are at same level. The arrangement is dipped in water. The height to which water will rise into the tube will be ($$\rho=$$ density of water, T = surface tension in water, g = acceleration due to gravity)

A
$$\frac{2 T}{\left(r_2-r_1\right) \rho g}$$
B
$$\frac{T}{\left(r_2^2-r_1^2\right) \rho g}$$
C
$$\frac{T}{\left(r_2-r_1\right) \rho g}$$
D
$$\frac{2 \mathrm{~T}}{\left(\mathrm{r}_2^2-\mathrm{r}_1^2\right) \rho g}$$
Questions Asked from MCQ (Single Correct Answer)
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