$$ \text { The solution set for the inequality } 13 x-5<15 x+4<7 x+12 ; x \in W \text { is } $$

The inequality $$4 x-3 \geq \frac{10 x-1}{3}$$ represents which of the following interval when $$x \in R$$

$$ \text { If } \frac{1}{2}\left(\frac{3 x}{5}+4\right) \geq \frac{1}{3}(x-6), x \in R \text { then } $$