Electromagnetism
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Alternating Current
MCQ (Single Correct Answer)
Modern Physics
Dual Nature of Radiation
MCQ (Single Correct Answer)
Semiconductor Devices and Logic Gates
MCQ (Single Correct Answer)
Communication Systems
MCQ (Single Correct Answer)
1
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The path difference between two identical light waves at a point $$Q$$ on the screen is $$3 \mu \mathrm{m}$$. If wavelength of the waves is $$5000 \mathop A\limits^o$$, then at point $$Q$$ there is

A
3rd dark band
B
4th bright band
C
5th dark band
D
6 th bright band
2
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Of the two slits producing interference in Young's experiment, one is covered with glass so that light intensity passing is reduced to $$50 \%$$. Which of the following is correct?

A
Intensity of fringes remains unaltered.
B
Intensity of bright fringe decreases and that of dark fringe increases.
C
Intensity of bright fringe increases and that of dark fringe decreases.
D
Intensity of both bright and dark fringes decreases.
3
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In a biprism experiment, monochromatic light of wavelength '$$\lambda$$' is used. The distance between two coherent sources '$$\mathrm{d}$$' is kept constant. If the distance between slit and eyepiece '$$\mathrm{D}$$' is varied as $$D_1, D_2, D_3 \& D_4$$ and corresponding measured fringe widths are $$Z_1, Z_2, Z_3$$ and $$Z_4$$ then

A
$$\mathrm{Z}_1 \mathrm{D}_1=\mathrm{Z}_2 \mathrm{D}_2=\mathrm{Z}_3 \mathrm{D}_3=\mathrm{Z}_4 \mathrm{D}_4$$
B
$$\frac{Z_1}{D_1}=\frac{Z_2}{D_2}=\frac{Z_3}{D_3}=\frac{Z_4}{D_4}$$
C
$$\mathrm{D}_1 \sqrt{\mathrm{Z}_1}=\mathrm{D}_2 \sqrt{\mathrm{Z}_2}=\mathrm{D}_3 \sqrt{\mathrm{Z}_3}=\mathrm{D}_4 \sqrt{\mathrm{Z}_4}$$
D
$$Z_1 \sqrt{D_1}=Z_2 \sqrt{D_2}=Z_3 \sqrt{D_3}=Z_4 \sqrt{D_4}$$
4
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$\mathrm{A}$$ and $$\mathrm{B}$$ are two interfering sources where $$\mathrm{A}$$ is ahead in phase by $$54^{\circ}$$ relative to B. The observation is taken from point $$\mathrm{P}$$ such that PB $$-$$ PA = 2.5 $$\lambda$$. Then the phase difference between the waves from A and B reaching point P is (in rad)

A
$$3.5 \pi$$
B
$$5.3 \pi$$
C
$$4.3 \pi$$
D
$$5.8 \pi$$
Questions Asked from MCQ (Single Correct Answer)
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