Electromagnetism
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Alternating Current
MCQ (Single Correct Answer)
Modern Physics
Dual Nature of Radiation
MCQ (Single Correct Answer)
Semiconductor Devices and Logic Gates
MCQ (Single Correct Answer)
Communication Systems
MCQ (Single Correct Answer)
1
MHT CET 2024 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In a diffraction pattern due to single slit of width ' $a$ ', the first minimum is observed at an angle $30^{\circ}$ when light of wavelength $5000 \mathop A\limits^o$ is incident on the slit. The first secondary maximum is observed at an angle $\left[\sin 30=\frac{1}{2}\right]$

A
$\sin ^{-1}\left(\frac{1}{2}\right)$
B
$\sin ^{-1}\left(\frac{3}{4}\right)$
C
$\sin ^{-1}\left(\frac{1}{4}\right)$
D
$\sin ^{-1}\left(\frac{3}{5}\right)$
2
MHT CET 2024 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In biprism experiment, if $5^{\text {th }}$ bright band with wavelength $\lambda_1$ coincides with $6^{\text {th }}$ dark band with wavelength $\lambda_2$ then the ratio $\left(\lambda_1 / \lambda_2\right)$ is

A
$\frac{7}{9}$
B
$\frac{10}{11}$
C
$\frac{11}{10}$
D
$\frac{9}{7}$
3
MHT CET 2024 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In young's double slit experiment, the $\mathrm{n}^{\text {th }}$ maximum of wavelength $\lambda_1$ is at a distance of $y_1$ from the central maximum. When the wavelength of the source is changed to $\lambda_2,\left(\frac{\mathrm{n}}{3}\right)^{\text {th }}$ maximum is at a distance of $y_2$ from its central maximum. The ratio $\frac{y_1}{y_2}$ is

A
$\frac{3 \lambda_1}{\lambda_2}$
B
$\frac{3 \lambda_2}{\lambda_1}$
C
$\frac{\lambda_1}{3 \lambda_2}$
D
$\frac{\lambda_2}{3 \lambda_1}$
4
MHT CET 2024 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In the Young's double slit experiment, the intensity at a point on the screen, where the path difference is $\lambda(\lambda=$ wavelength $)$ is $\beta$. The intensity at a point where the path difference is $\lambda / 3$, will be $\left.\cos \frac{\pi}{3}=1 / 2\right]$

A
$\beta$
B
$\beta / 2$
C
$\frac{\beta}{4}$
D
$\beta / 8$
Questions Asked from MCQ (Single Correct Answer)
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