Algebra
Sets and Relations
MCQ (Single Correct Answer)Logarithms
MCQ (Single Correct Answer)Quadratic Equations
MCQ (Single Correct Answer)Sequences and Series
MCQ (Single Correct Answer)Binomial Theorem
MCQ (Single Correct Answer)Permutations and Combinations
MCQ (Single Correct Answer)Probability
MCQ (Single Correct Answer)Vector Algebra
MCQ (Single Correct Answer)Three Dimensional Geometry
MCQ (Single Correct Answer)Matrices and Determinants
MCQ (Single Correct Answer)Statistics
MCQ (Single Correct Answer)Mathematical Reasoning
MCQ (Single Correct Answer)Linear Programming
MCQ (Single Correct Answer)Complex Numbers
MCQ (Single Correct Answer)Trigonometry
Trigonometric Ratios & Identities
MCQ (Single Correct Answer)Trigonometric Equations
MCQ (Single Correct Answer)Inverse Trigonometric Functions
MCQ (Single Correct Answer)Properties of Triangles
MCQ (Single Correct Answer)Calculus
Functions
MCQ (Single Correct Answer)Limits, Continuity and Differentiability
MCQ (Single Correct Answer)Differentiation
MCQ (Single Correct Answer)Application of Derivatives
MCQ (Single Correct Answer)Indefinite Integration
MCQ (Single Correct Answer)Definite Integration
MCQ (Single Correct Answer)Area Under The Curves
MCQ (Single Correct Answer)Differential Equations
MCQ (Single Correct Answer)Coordinate Geometry
Straight Lines and Pair of Straight Lines
MCQ (Single Correct Answer)Parabola
MCQ (Single Correct Answer)Ellipse
MCQ (Single Correct Answer)Hyperbola
MCQ (Single Correct Answer)1
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+2
-0
For a set of five true or false questions, no student has written the all correct answers and no two students have given the same sequence of answers. The maximum number of students in the class for this to be possible is
2
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+2
-0
The number of ways in which 8 different pearls can be arranged to form a necklace is
3
MHT CET 2021 20th September Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $$\frac{n !}{2 !(n-2) !}$$ and $$\frac{n !}{4 !(n-4) !}$$ are in the ratio $$2: 1$$, then $$n=$$
4
MHT CET 2021 20th September Morning Shift
MCQ (Single Correct Answer)
+2
-0
All the letters of the word 'ABRACADABRA' are arranged in different possible ways. Then the number of such arrangements in which the vowels are together is
Questions Asked from MCQ (Single Correct Answer)
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MHT CET Subjects
Physics
Mechanics
Optics
Electromagnetism
Chemistry
Physical Chemistry
Inorganic Chemistry
Mathematics
Algebra
Trigonometry
Calculus
Coordinate Geometry