GATE ME 2009 | Pert and Cpm Question 17 | Industrial Engineering

The expected time $$\left( {{t_e}} \right)$$ of a $$PERT$$ activity in terms of optimistic time $$\left( {{t_0}} \right)$$, pessimistic $$\left( {{t_p}} \right)$$ and most likely time $$\left( {{t_L}} \right)$$ is given by

$${t_e} = {{{t_0} + 4{t_L} + {t_P}} \over 6}$$

$${t_e} = {{{t_0} + 4{t_P} + {t_L}} \over 6}$$

$${t_e} = {{{t_0} + 4{t_L} + {t_P}} \over 3}$$

$${t_e} = {{{t_0} + 4{t_P} + {t_L}} \over 3}$$

GATE ME 2004

MCQ (Single Correct Answer)

-0.3

In $$PERT$$ analysis a critical activity has

maximum Float

zero Float

maximum Cost

minimum Cost

GATE ME 1997

MCQ (Single Correct Answer)

-0.3

A dummy activity is used in $$PERT$$ network to describe

Precedence relationship

Necessary time delay

Resource restriction

Resource idleness

GATE ME 1995

MCQ (Single Correct Answer)

-0.3

In $$PERT,$$ the distribution of activity times is assumed to be

Normal

Gamma

Beta

Exponential

Questions Asked from Marks 1

GATE ME 2017 Set 2 (1) GATE ME 2016 Set 3 (1) GATE ME 2014 (1) GATE ME 2009 (1) GATE ME 2004 (1) GATE ME 1997 (1) GATE ME 1995 (1)

GATE ME Subjects

Engineering Mechanics

Machine Design

Strength of Materials

Heat Transfer

Production Engineering

Industrial Engineering

Turbo Machinery

Theory of Machines

Engineering Mathematics

Fluid Mechanics

Thermodynamics

General Aptitude