CBSE 12th Physics Outside Delhi Set 1 - 2023 | Current Electricity Question 8 | Physics

A cell of emf $$E$$ is connected across an external resistance $$R$$. When current '$$I$$' is drawn from the cell, the potential difference across the electrodes of the cell drops to $$\mathrm{V}$$. The internal resistance '$$r$$' of the cell is

$$\left(\frac{E-V}{E}\right) R$$

$$\left(\frac{E-V}{R}\right)$$

$$\frac{(E-V) R}{I}$$

$$\left(\frac{(E-V)}{V}\right) R$$

Questions Asked from Marks 1

CBSE 12th Physics Delhi Set 1 - 2024 (2) CBSE 12th Physics Delhi Set 1 - 2023 (1) CBSE 12th Physics Outside Delhi Set 1 - 2023 (2)

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