$\int \frac{1}{x(\log x)^2} d x$ is equal to

$$\int \frac{\sec x}{\sec x-\tan x} d x$$ equals:

(a) Find: $\int \cos ^3 x e^{\log \sin x} d x$

OR

(b) Find: $\int \frac{1}{5+4 x-x^2} d x$