Algebra
Quadratic Equations
MCQ (Single Correct Answer)
Sequences and Series
MCQ (Single Correct Answer)
Permutations and Combinations
MCQ (Single Correct Answer)
Sets and Relations
MCQ (Single Correct Answer)
Three Dimensional Geometry
MCQ (Single Correct Answer)
Matrices and Determinants
MCQ (Single Correct Answer)
Trigonometry
Trigonometric Ratios & Identities
MCQ (Single Correct Answer)
Trigonometric Equations
MCQ (Single Correct Answer)
Inverse Trigonometric Functions
MCQ (Single Correct Answer)
Properties of Triangles
MCQ (Single Correct Answer)
Calculus
Limits, Continuity and Differentiability
MCQ (Single Correct Answer)
Application of Derivatives
MCQ (Single Correct Answer)
Indefinite Integration
MCQ (Single Correct Answer)
Definite Integration
MCQ (Single Correct Answer)
Area Under The Curves
MCQ (Single Correct Answer)
Differential Equations
MCQ (Single Correct Answer)
Coordinate Geometry
Straight Lines and Pair of Straight Lines
MCQ (Single Correct Answer)
1
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The power of a point $(2,0)$ with respect to a circle $S$ is -4 and the length of the tangent drawn from the point $(1,1)$ to $S$ is 2 . If the circle $S$ passes through the point $(-1,-1)$, then the radius of the circle $S$ is
A
2
B
$\sqrt{13}$
C
3
D
$\sqrt{10}$
2
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The pole of the line $x-5 y-7=0$ with respect to the circle $S \equiv x^2+y^2-2 x+4 y+1=0$ is $P(a, b)$. If $C$ is the centre of the circle $S=0$, then $P C=$
A
$\sqrt{a+b-1}$
B
$\sqrt{a^2+b^2-1}$
C
$\sqrt{a^3+b^3-1}$
D
$3 a b$
3
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The equation of the pair of transverse common tangents drawn to the circles $x^2+y^2+2 x+2 y+1=0$ and $x^2+y^2-2 x-2 y+1=0$ is
A
$x^2-y^2=0$
B
$x y=0$
C
$x^2-y^2+2 x+1=0$
D
$x^2-y^2-2 y-1=0$
4
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If a circle passing through the point $(1,1)$ cuts the circles $x^2+y^2+4 x-5=0$ and $x^2+y^2-4 y+3=0$ orthogonally, then the centre of that circle is
A
$\left(\frac{3}{4}, \frac{5}{4}\right)$
B
$\left(\frac{3}{2}, \frac{5}{2}\right)$
C
$\left(-\frac{3}{2},-\frac{5}{2}\right)$
D
$\left(-\frac{3}{4},-\frac{5}{2}\right)$
TS EAMCET Subjects