Algebra
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MCQ (Single Correct Answer)Logarithms
MCQ (Single Correct Answer)Quadratic Equations
MCQ (Single Correct Answer)Sequences and Series
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MCQ (Single Correct Answer)Probability
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MCQ (Single Correct Answer)Binomial Theorem
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MCQ (Single Correct Answer)Three Dimensional Geometry
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MCQ (Single Correct Answer)Statistics
MCQ (Single Correct Answer)Trigonometry
Trigonometric Ratios & Identities
MCQ (Single Correct Answer)Trigonometric Equations
MCQ (Single Correct Answer)Inverse Trigonometric Functions
MCQ (Single Correct Answer)Properties of Triangles
MCQ (Single Correct Answer)Calculus
Functions
MCQ (Single Correct Answer)Limits, Continuity and Differentiability
MCQ (Single Correct Answer)Differentiation
MCQ (Single Correct Answer)Application of Derivatives
MCQ (Single Correct Answer)Indefinite Integration
MCQ (Single Correct Answer)Definite Integration
MCQ (Single Correct Answer)Area Under The Curves
MCQ (Single Correct Answer)Differential Equations
MCQ (Single Correct Answer)Coordinate Geometry
Straight Lines and Pair of Straight Lines
MCQ (Single Correct Answer)Parabola
MCQ (Single Correct Answer)Ellipse
MCQ (Single Correct Answer)Hyperbola
MCQ (Single Correct Answer)1
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The number of normals that can be drawn through the point $(9,6)$ to the parabola $y^2=4 x$ is
2
TG EAPCET 2024 (Online) 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If $(2,3)$ is the focus and $x-y+3=0$ is the directrix of a parabola, then the equation of the tangent drawn at the vertex of the parabola is
3
TG EAPCET 2024 (Online) 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The equation of the common tangent to the parabola $y^2=8 x$ and the circle $x^2+y^2=2$ is $a x+b y+2=0$. If $-\frac{a}{b}>0$, then $3 a^2+2 b+1=$
4
TG EAPCET 2024 (Online) 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
Consider the parabola $25\left[(x-2)^2+(y+5)^2\right]=(3 x+4 y-1)^2$, match the characteristic of this parabola given in List I with its corresponding item in List II.
$$ \begin{array}{lll} \hline & \text { List I } & \text { List II } \\\\ \hline \text { I } & \text { Vertex } & \text { (A) } 8 \\\\ \hline \text { II } & \text { length of latus rectum } & \text { (B) }\left(\frac{29}{10}, \frac{-38}{10}\right) \\\\ \hline \text { III } & \text { Directrix } & \text { (C) } 3 x+4 y-1=0 \\\\ \hline \text { IV } & \begin{array}{l} \text { One end of the latus } \\\\ \text { rectum } \end{array} & \text { (D) }\left(\frac{-2}{5}, \frac{-16}{5}\right) \\\\ \hline \end{array} $$
The correct answer is
Questions Asked from MCQ (Single Correct Answer)
TG EAPCET 2024 (Online) 11th May Morning Shift (2) TG EAPCET 2024 (Online) 10th May Evening Shift (1) TG EAPCET 2024 (Online) 10th May Morning Shift (2) TG EAPCET 2024 (Online) 9th May Evening Shift (2) TG EAPCET 2024 (Online) 9th May Morning Shift (3) TS EAMCET 2023 (Online) 12th May Morning Shift (2)
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Mathematics
Algebra
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