Electromagnetism
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Alternating Current
MCQ (Single Correct Answer)
Modern Physics
Dual Nature of Radiation
MCQ (Single Correct Answer)
Semiconductor Devices and Logic Gates
MCQ (Single Correct Answer)
Communication Systems
MCQ (Single Correct Answer)
1
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two identical current carrying coils with same centre are placed with their planes perpendicular to each other. If current $\mathrm{I}=\sqrt{2} \mathrm{~A}$ and radius of the coil is $R=1 \mathrm{~m}$, then magnetic field at centre is equal to ( $\mu_0=$ permeability of free space)

A
$\mu_0$
B
$\frac{\mu_0}{2}$
C
$2 \mu_0$
D
$\sqrt{2} \mu_0$
2
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Figure shows two semicircular loops of radii $$R_1$$ and $$R_2$$ carrying current $I$. The magnetic field at the common centre '$$\mathrm{O}$$' is

MHT CET 2023 14th May Evening Shift Physics - Moving Charges and Magnetism Question 73 English

A
$$\frac{\mu_0 \mathrm{I}}{4}\left(\frac{1}{\mathrm{R}_1}+\frac{1}{\mathrm{R}_2}\right)$$
B
$$\frac{\mu_0 \mathrm{I}}{4}\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right)$$
C
$$\frac{\mu_0 \mathrm{I}}{2 \pi}\left(\frac{1}{\mathrm{R}_1}+\frac{1}{\mathrm{R}_2}\right)$$
D
$$\frac{\mu_0 I}{2 \pi}\left(\frac{1}{R_1}-\frac{1}{R_2}\right)$$
3
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A long wire is bent into a circular coil of one turn and then into a circular coil of smaller radius having $$\mathrm{n}$$ turns. If the same current passes in both the cases, the ratio of magnetic fields produced at the centre for one turn to that of $$n$$ turns is

A
$$1: \mathrm{n}$$
B
$$\mathrm{n}: 1$$
C
$$1: \mathrm{n}^2$$
D
$$\mathrm{n}^2: 1$$
4
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A horizontal wire of mass '$$m$$', length '$$l$$' and resistance '$$R$$' is sliding on the vertical rails on which uniform magnetic field '$$B$$' is directed perpendicular. The terminal speed of the wire as it falls under the force of gravity is ( $$\mathrm{g}=$$ acceleration due to gravity)

A
$$\frac{\mathrm{mg} l}{\mathrm{BR}}$$
B
$$\frac{\mathrm{B}^2 l^2}{\mathrm{mgR}}$$
C
$$\frac{\mathrm{mgR}}{\mathrm{Bl}}$$
D
$$\frac{\mathrm{mgR}}{\mathrm{B}^2 l^2}$$
Questions Asked from MCQ (Single Correct Answer)
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