Consider the following pairs.

$$ \begin{array}{l|l|l} \hline & \text { Order } & \text { Property } \\ \hline \text { (A) } & \mathrm{NO}_2>\mathrm{O}_3>\mathrm{H}_2 \mathrm{O} & \text { Bond angle } \\ \hline \text { (B) } & \mathrm{HF}>\mathrm{H}_2 \mathrm{O}>\mathrm{NH}_3 & \text { Dipole moment } \\ \hline \text { (C) } & \mathrm{I}_2>\mathrm{F}_2>\mathrm{N}_2 & \text { Bond length } \\ \hline \end{array} $$

Which of the above pairs are correctly matched?

In which of the following set of molecules the hybridisation of central atoms is different?

$$ \underset{(1: 20)}{\mathrm{Xe}(g)+\mathrm{F}_2(\mathrm{~g}) \xrightarrow[60-70 \text { bar }]{573 \mathrm{~K}} X(\mathrm{~s})} $$ $$ X+\mathrm{H}_2 \mathrm{O} \longrightarrow Y+\mathrm{HF}, X+3 \mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Z}+\mathrm{HF} $$ The correct statements regarding $Y$ and $Z$ are (I) $Y$ has square pyramidal geometry. (II) $Y$ has linear geometry. (III) Z has $3 \sigma, 3 \pi$ bonds and 1 lone pair of electrons on the central atom. (IV) Z has tetrahedral geometry.

Table Match the following. The correct answer is