Electromagnetism
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Alternating Current
MCQ (Single Correct Answer)
Modern Physics
Dual Nature of Radiation
MCQ (Single Correct Answer)
Semiconductor Devices and Logic Gates
MCQ (Single Correct Answer)
Communication Systems
MCQ (Single Correct Answer)
1
MHT CET 2024 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A lead bullet moving with velocity ' V ' strikes a wall and stops. If $75 \%$ of its energy is converted into heat, then the increase in temperature is ( $\mathrm{s}=$ specific heat of lead, $\mathrm{J}=$ mechanical equivalent of heat)

A
$\frac{3 \mathrm{~V}^2}{8 \mathrm{Js}}$
B
$\frac{5 \mathrm{~V}^2}{8 \mathrm{Js}}$
C
$\frac{3 \mathrm{~V}^2}{4 \mathrm{Js}}$
D
$\frac{5 \mathrm{~V}^2}{4 \mathrm{Js}}$
2
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The potential energy of a long spring when it is stretched by 3 cm is ' $U$ '. If the spring is stretched by 9 cm , potential energy stored in it will be

A
3U
B
4U
C
5U
D
9U
3
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A carpet of mass ' $M$ ' made of a material is rolled along its length in the form of a cylinder of radius ' $R$ ' and kept above the rough floor. If the carpet is unrolled without sliding to a radius ' $R / 2$ '. The change in potential energy is ( $\mathrm{g}=$ acceleration due to gravity)

A
MgR
B
$\frac{7}{8} \mathrm{MgR}$
C
$\frac{5}{7} \mathrm{MgR}$
D
$\frac{3}{4} \mathrm{MgR}$
4
MHT CET 2024 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A ball ' $A$ ' is projected vertically upwards with certain initial speed. Another ball 'B' of same mass is projected at an angle of $30^{\circ}$ with vertical with the same initial speed. At the highest point, the ratio of potential energy of ball A to that of ball B will be

$$\left(\sin 90^{\circ}=1, \sin 60^{\circ}=\cos 30^{\circ}=\frac{\sqrt{3}}{2}, \sin 30^{\circ}=\cos 60^{\circ}=\frac{1}{2}\right)$$

A
$4: 3$
B
$3: 4$
C
$4: 1$
D
$3: 2$
MHT CET Subjects