Electromagnetism
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Alternating Current
MCQ (Single Correct Answer)
Modern Physics
Dual Nature of Radiation
MCQ (Single Correct Answer)
Semiconductor Devices and Logic Gates
MCQ (Single Correct Answer)
Communication Systems
MCQ (Single Correct Answer)
1
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A current of 0.5 A is passed through winding of a long solenoid having 400 turns. The magnetic flux linked with each turn is $3 \times 10^{-3} \mathrm{~Wb}$. The self inductance of the solenoid is

A
2.4 H
B
2.0 H
C
1.2 H
D
0.6 H
2
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A square loop of area $25 \mathrm{~cm}^2$ has a resistance of $10 \Omega$. The loop is placed in uniform magnetic field of magnitude 40 T . The plane of loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic field slowly and uniformly in 1 second, will be

A
$2.5 \times 10^{-3} \mathrm{~J}$
B
$1.0 \times 10^{-3} \mathrm{~J}$
C
$1.0 \times 10^{-4} \mathrm{~J}$
D
$5 \times 10^{-3} \mathrm{~J}$
3
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A graph of magnetic flux $(\phi)$ versus current ( 1 ) is shown for four inductors A, B, C, D. Smaller value of self inductance is for inductor

MHT CET 2024 4th May Morning Shift Physics - Electromagnetic Induction Question 29 English

A
D
B
C
C
B
D
A
4
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A circular coil of resistance $R$, area $A$, number of turns ' $N$ ' is rotated about its vertical diameter with angular speed ' $\omega$ ' in a uniform magnetic field of magnitude ' $B$ '. The average power dissipated in a complete cycle is

A
$\frac{\mathrm{N}^2 \mathrm{~A}^2 \mathrm{~B}^2 \omega^2}{2 \mathrm{R}}$
B
$\frac{\mathrm{BNA} \omega}{\mathrm{R}}$
C
$\frac{\mathrm{N}^2 \mathrm{AB}}{2 \mathrm{R} \omega^2}$
D
$\frac{B A \omega}{2 N R}$
Questions Asked from MCQ (Single Correct Answer)
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