Thermodynamics
Calculation of Work and Heat
Marks 1Marks 2
Entropy and Irreversibility
Marks 1Marks 2Marks 5
Properties of Pure Substances
Marks 1Marks 2
Basic Concepts and Zeroth Law
Marks 1Marks 2
First Law of Thermodynamics
Marks 1Marks 2Marks 5
Second Law of Thermodynamics
Marks 1Marks 2
1
GATE ME 1995
MCQ (Single Correct Answer)
+1
-0.3
Consider a refrigerator and a heat pump working on the reversed Carnot cycle between the same temperature limits. Which of the following is correct?
A
$$COP$$ refrigerator $$= COP$$ of heat pump
B
$$COP$$ of refrigerator $$= COP$$ of heat pump $$+ 1$$
C
$$COP$$ of refrigerator $$= COP$$ of heat pump $$- 1$$
D
$$COP$$ of refrigerator $$=$$ inverse $$COP$$ of heat pump
2
GATE ME 1995
Fill in the Blanks
+1
-0
In the case of a refrigeration system undergoing an irreversible cycle, $$\oint {{{SQ} \over T}} $$ is _____________$$\left( { < 0/ = 0/ > 0} \right)$$
3
GATE ME 1994
True or False
+1
-0
Any thermodynamic cycle operating between two temperature limits is reversible if the product of efficiency when operating as a heat engine and the coefficient of performance when operating as a refrigeration is equal to $$1.$$
A
TRUE
B
FALSE
4
GATE ME 1993
MCQ (Single Correct Answer)
+1
-0.3
A reversible heat transfer demands:
A
The temperature difference causing heat transfer tends to zero
B
The system receiving heat must be at a constant temperature.
C
The system transferring out heat must be at a constant temperature.
D
Both interacting systems must be at constant temperatures
GATE ME Subjects
Engineering Mechanics
Machine Design
Strength of Materials
Heat Transfer
Production Engineering
Industrial Engineering
Turbo Machinery
Theory of Machines
Engineering Mathematics
Fluid Mechanics
Thermodynamics
General Aptitude