AIPMT 2009 | Properties of Matter Question 66 | Physics

The two ends of a rod of length L and a uniform cross-sectional area A are Kept at two temperatures T₁ and T₂ (T₁ > T₂). The rate of heat transfer, $${{dQ} \over {dt}}$$ through the rod in a steady state is given by :

$${{dQ} \over {dt}} = {{k\left( {{T_1} - {T_2}} \right)} \over {LA}}$$

$${{dQ} \over {dt}} = kLA({T_1} - {T_2})$$

$${{dQ} \over {dt}} = {{kA\left( {{T_1} - {T_2}} \right)} \over L}$$

$${{dQ} \over {dt}} = {{kL\left( {{T_1} - {T_2}} \right)} \over A}$$

AIPMT 2009

MCQ (Single Correct Answer)

-1

A black body at 227^oC radiates heat at the rate of 7 cals/cm²s. At a temperature of 727^oC, the rate of heat radiated in the same units will be

112

AIPMT 2008

MCQ (Single Correct Answer)

-1

On a new scale of temperature (which is linear) and called the W scale, the freezing and boiling points of water are 39^oW and 239^oW respectively. What will be the temperature on the new scale, corresponding to a temperature of 39^oC on the Celsius scale ?

200^oW

139^oW

78^oW

117^oW

AIPMT 2007

MCQ (Single Correct Answer)

-1

A black body is at 727^oC. It emits energy at a rate which is proportional to

(1000)⁴

(1000)²

(727)⁴

(727)²

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