Organic Chemistry
Some Basic Concepts of Organic Chemistry
MCQ (Single Correct Answer)MCQ (Multiple Correct Answer)
Alcohol, Phenols and Ethers
MCQ (Single Correct Answer)
Aldehydes, Ketones and Carboxylic Acids
MCQ (Single Correct Answer)MCQ (Multiple Correct Answer)
Organic Compounds Containing Nitrogen
MCQ (Single Correct Answer)
Chemistry in Everyday Life
MCQ (Single Correct Answer)
1
AIPMT 2006
MCQ (Single Correct Answer)
+4
-1
The hydrogen ion concentration of a 10$$-$$8 M, HCl aqueous solution at 298 K (Kw = 10$$-$$14) is
A
1.0 $$ \times $$ 10$$-$$8 M
B
1.0 $$ \times $$ 10$$-$$6 M
C
1.0525 $$ \times $$ 10$$-$$7 M
D
9.525 $$ \times $$ 10$$-$$8 M
2
AIPMT 2005
MCQ (Single Correct Answer)
+4
-1
At 25oC, the dissociation constant of a base, BOH, is 1.0 $$ \times $$ 10$$-$$12. The concentration of hydroxyl ions in 0.01 M aqueous solution of the base would be
A
1.0 $$ \times $$ 10$$-$$5 mol L$$-$$1
B
1.0 $$ \times $$ 10$$-$$6 mol L$$-$$1
C
2.0 $$ \times $$ 10$$-$$6 mol L$$-$$1
D
1.0 $$ \times $$ 10$$-$$7 mol L$$-$$1
3
AIPMT 2005
MCQ (Single Correct Answer)
+4
-1
H2S gas when passed through a solution of cations containing HCl precipitates the cations of second group of qualitative analysis but not those belonging to the fourth group. It is because
A
presence of HCl decreases the sulphide ion concentration
B
solubility product of group II sulphides is more than that of group IV sulphates
C
presence of HCl increases the sulphide ion concentration
D
sulphides of group IV cations are unstable in HCl.
4
AIPMT 2004
MCQ (Single Correct Answer)
+4
-1
The rapid change of pH near the stoichiometric point of an acid-base titration is the basis of indicator detection. pH of the solution is related to ratio of the concentrations of the conjugate acid (HIn) and base (In$$-$$) forms of the indicator by the expression
A
$$\log {{\left[ {I{n^ - }} \right]} \over {\left[ {HIn} \right]}} = p{K_{In}} - pH$$
B
$$\log {{\left[ {HIn} \right]} \over {\left[ {I{n^ - }} \right]}} = p{K_{In}} - pH$$
C
$$\log {{\left[ {HIn} \right]} \over {\left[ {I{n^ - }} \right]}} = pH - p{K_{In}}$$
D
$$\log {{\left[ {I{n^ - }} \right]} \over {\left[ {HIn} \right]}} = pH - p{K_{In}}$$
NEET Subjects