AIPMT 2009 | Electromagnetic Waves Question 27 | Physics

The electric field part of an electromagnetic wave in a medium is represented by E_x = 0;

$${E_y} = 2.5{N \over C}\cos \left[ {\left( {2\pi \times {{10}^6}{{rad} \over m}} \right)t - \left( {\pi \times {{10}^{ - 2}}{{rad} \over s}} \right)x} \right];$$

E_z = 0.

moving along x direction with frequency 10⁶ Hz and wavelength 100 m.

moving along x direction with frequency 10⁶ Hz and wavelength 200 m.

moving along $$-$$x direction with frequency 10⁶ Hz and wavelength 200 m.

moving along y direction with frequency $$2\pi \times {10^6}\,Hz$$ and wavelength 200 m.

AIPMT 2008

MCQ (Single Correct Answer)

-1

The velocity of electromagnetic radiation in a medium of permittivity $$\varepsilon $$₀ and permeability $$\mu $$₀ is given by

$${1 \over {\sqrt {{\mu _0}{\varepsilon _0}} }}$$

$$\sqrt {{{{\mu _0}} \over {{\varepsilon _0}}}} $$

$$\sqrt {{{{\varepsilon _0}} \over {{\mu _0}}}} $$

$$\sqrt {{\mu _0}{\varepsilon _0}} $$

AIPMT 2007

MCQ (Single Correct Answer)

-1

The electric and magnetic field of an electromagnetic wave are

in opposite phase and perpendicular to each other

in opposite phase and parallel to each other

in phase and perpendicular to each other

in phase and parallel to each other.

AIPMT 2005

MCQ (Single Correct Answer)

-1

If $$\lambda $$_v, $$\lambda $$_x and $$\lambda $$_m represent the wavelengths of visible light, X-rays and microwaves respectively, then

$${\lambda _m} > {\lambda _x} > {\lambda _v}$$

$${\lambda _m} > {\lambda _v} > {\lambda _x}$$

$${\lambda _v} > {\lambda _x} > {\lambda _m}$$

$${\lambda _v} > {\lambda _m} > {\lambda _x}$$

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