NEET 2017 | Dual Nature of Radiation and Matter Question 23 | Physics

Electrons of mass m with de-Broglie wavelength $$\lambda $$ fall on the target in an X-ray tube. The cutoff wavelength ($$\lambda $$₀) of the emitted X-ray is

$$\lambda $$₀ = $${{2mc{\lambda ^2}} \over h}$$

$${\lambda _0} = {{2h} \over {mc}}$$

$${\lambda _0} = {{2{m^2}{c^2}{\lambda ^3}} \over {{h^2}}}$$

$${\lambda _0} = \lambda $$

NEET 2016 Phase 2

MCQ (Single Correct Answer)

-1

Photons with energy 5 eV are incifent on a cathode C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C, no photoelectrons will reach the anode A, if the stopping potential of A relative to C is

+ 3 V

+4 V

$$-$$1 V

$$-$$3 V

NEET 2016 Phase 1

MCQ (Single Correct Answer)

-1

An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelengths associated with them is

$$c{\left( {2mE} \right)^{{1 \over 2}}}$$

$${1 \over c}{\left( {{{2m} \over E}} \right)^{{1 \over 2}}}$$

$${1 \over c}{\left( {{E \over {2m}}} \right)^{{1 \over 2}}}$$

$${\left( {{E \over {2m}}} \right)^{{1 \over 2}}}$$

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