NEET 2024 | Electromagnetic Waves Question 4 | Physics

In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $$2.0 \times 10^{10} \mathrm{~Hz}$$ and amplitude $$48 ~\mathrm{Vm}^{-1}$$. Then the amplitude of oscillating magnetic field is : (Speed of light in free space $$=3 \times 10^{8} \mathrm{~m} \mathrm{~s}^{-1}$$ )

$$1.6 \times 10^{-8} \mathrm{~T}$$

$$1.6 \times 10^{-7} \mathrm{~T}$$

$$1.6 \times 10^{-6} \mathrm{~T}$$

$$1.6 \times 10^{-9} \mathrm{~T}$$

NEET 2022 Phase 2

MCQ (Single Correct Answer)

-1

The magnetic field of a plane electromagnetic wave is given by $$\overrightarrow B = 3 \times {10^{ - 8}}\cos (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat j$$, then the associated electric field will be :

$$9\cos (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat k$$ V/m

$$3 \times {10^{ - 8}}\cos (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat i$$ V/m

$$3 \times {10^{ - 8}}\sin (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat i$$ V/m

$$9\sin (1.6 \times {10^3}x - 48 \times {10^{10}}t)\widehat k$$ V/m

NEET 2022 Phase 2

MCQ (Single Correct Answer)

-1

The ratio of the magnitude of the magnetic field and electric field intensity of a plane electromagnetic wave in free space of permeability $${\mu _0}$$ and permittivity $${\varepsilon _0}$$ is (Given that c - velocity) of light in free space

$${{\sqrt {{\mu _0}{\varepsilon _0}} } \over c}$$

$${1 \over c}$$

$${c \over {\sqrt {{\mu _0}{\varepsilon _0}} }}$$

Previous Next

NEET Subjects

Biology

Zoology

Human Health and Diseases Body Fluids and Its Circulation Locomotion and Movement Neural Control and Coordination Reproduction in Organisms Reproductive Health Structural Organisation in Animals Digestion and Absorption Excretory Products and Their Elimination Chemical Coordination and Integration Human Reproduction Animal Kingdom Breathing and Exchange of Gases Evolution