If $$x=5 \sin \left(\pi t+\frac{\pi}{3}\right) \mathrm{m}$$ represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are
If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is $$\frac{x}{2}$$ times its original time period. Then the value of $$x$$ is:
A simple pendulum oscillating in air has a period of $$\sqrt{3} \mathrm{~s}$$. If it is completely immersed in non-viscous liquid, having density $$\left(\frac{1}{4}\right)^{\text {th }}$$ of the material of the bob, the new period will be :-
The $$x$$ - $$t$$ graph of a particle performing simple harmonic motion is shown in the figure. The acceleration of the particle at $$t=2 \mathrm{~s}$$ is :
