Electricity
Current Electricity
MCQ (Single Correct Answer)
Moving Charges and Magnetism
MCQ (Single Correct Answer)
Magnetism and Matter
MCQ (Single Correct Answer)
Electromagnetic Induction
MCQ (Single Correct Answer)
Electromagnetic Waves
MCQ (Single Correct Answer)
Modern Physics
Semiconductor Electronics
MCQ (Single Correct Answer)
1
NEET 2024 (Re-Examination)
MCQ (Single Correct Answer)
+4
-1

If the ratio of relative permeability and relative permittivity of a uniform medium is $$1: 4$$. The ratio of the magnitudes of electric field intensity $$(E)$$ to the magnetic field intensity $$(H)$$ of an EM wave propagating in that medium is (Given that $$\sqrt{\frac{\mu_0}{\varepsilon_0}}=120 \pi$$):

A
$$30 \pi: 1$$
B
$$1: 120 \pi$$
C
$$60 \pi: 1$$
D
$$120 \pi: 1$$
2
NEET 2024
MCQ (Single Correct Answer)
+4
-1

The property which is not of an electromagnetic wave travelling in free space is that:

A
They are transverse in nature
B
The energy density in electric field is equal to energy density in magnetic field
C
They travel with a speed equal to $$\frac{1}{\sqrt{\mu_0 \varepsilon_0}}$$
D
They originate from charges moving with uniform speed
3
NEET 2023
MCQ (Single Correct Answer)
+4
-1

In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $$2.0 \times 10^{10} \mathrm{~Hz}$$ and amplitude $$48 ~\mathrm{Vm}^{-1}$$. Then the amplitude of oscillating magnetic field is : (Speed of light in free space $$=3 \times 10^{8} \mathrm{~m} \mathrm{~s}^{-1}$$ )

A
$$1.6 \times 10^{-8} \mathrm{~T}$$
B
$$1.6 \times 10^{-7} \mathrm{~T}$$
C
$$1.6 \times 10^{-6} \mathrm{~T}$$
D
$$1.6 \times 10^{-9} \mathrm{~T}$$
4
NEET 2022 Phase 2
MCQ (Single Correct Answer)
+4
-1

The magnetic field of a plane electromagnetic wave is given by $$\overrightarrow B = 3 \times {10^{ - 8}}\cos (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat j$$, then the associated electric field will be :

A
$$9\cos (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat k$$ V/m
B
$$3 \times {10^{ - 8}}\cos (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat i$$ V/m
C
$$3 \times {10^{ - 8}}\sin (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat i$$ V/m
D
$$9\sin (1.6 \times {10^3}x - 48 \times {10^{10}}t)\widehat k$$ V/m
NEET Subjects